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2002 AMC 10A Problem 24

Problem 24 of 25HarderCounting & Probability

Tina randomly selects two distinct numbers from the set {1,2,3,4,5},\{1,2,3,4,5\}, and Sergio randomly selects a number from the set {1,2,,10}.\{1,2,\ldots,10\}. The probability that Sergio’s number is larger than the sum of the two numbers chosen by Tina is

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Solution

Tina’s 1010 equally likely pairs give sums 3,3, 4,4, 5,5, 5,5, 6,6, 6,6, 7,7, 7,7, 8,8, and 9.9. For a sum s,s, Sergio’s number exceeds it with probability 10s10.\dfrac{10-s}{10}. Averaging the winning probability over the ten pairs, the total is 7+6+5+5+4+4+3+3+2+1100\small\dfrac{7+6+5+5+4+4+3+3+2+1}{100} =40100=25.=\dfrac{40}{100}=\dfrac{2}{5}. Thus, the correct answer is A.

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Concepts: basic probability · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.