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2007 AMC 10A Problem 24

Problem 24 of 25HarderGeometry

Circles centered at AA and BB each have radius 2,2, as shown. Point OO is the midpoint of AB‾,\overline{AB}, and OA=22.OA = 2\sqrt{2}. Segments OCOC and ODOD are tangent to the circles centered at AA and B,B, respectively, and EF‾\overline{EF} is a common tangent. What is the area of the shaded region ECODF?ECODF?

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Solution

Rectangle ABFEABFE has area AE⋅AB=2⋅42=82.AE \cdot AB = 2 \cdot 4\sqrt2 = 8\sqrt2. Right triangles ACOACO and BDOBDO each have hypotenuse 222\sqrt2 and a leg of 2,2, so each is isosceles right with area 2.2. Angles CAECAE and DBFDBF are each 45∘,45^\circ, so sectors CAECAE and DBFDBF each have area 18π⋅22=π2.\tfrac18 \pi \cdot 2^2 = \tfrac{\pi}{2}. The shaded area is 82−2⋅2−2⋅π2=82−4−π. \begin{gathered} 8\sqrt2 - 2 \cdot 2 - 2 \cdot \tfrac{\pi}{2} \\ = 8\sqrt2 - 4 - \pi. \end{gathered} Thus, the correct answer is B.
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Tagged: tangent line · sector · area decomposition

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