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2011 AMC 10A Problem 3

Problem 3 of 25EasierAlgebra

Suppose [a b][a\ b] denotes the average of aa and b,b, and {a b c}\{a\ b\ c\} denotes the average of a,a, b,b, and c.c. What is the value of the following expression? {{1 1 0} [0 1] 0}\{\{1 \ 1 \ 0\} \ [0 \ 1] \ 0\}

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Solution

We have that {1 1 0}=1+1+03=23. \{1 \ 1 \ 0\} = \dfrac{1 + 1 + 0}{3} = \dfrac{2}{3}. We also get that [0 1]=1+02=12. [0 \ 1] = \dfrac{1 + 0}{2} = \dfrac{1}{2}. Finally, {23 12 0}=23+12+03=718. \left\{\dfrac{2}{3} \ \dfrac{1}{2} \ 0\right\} = \dfrac{\dfrac{2}{3} + \dfrac{1}{2} + 0}{3} = \dfrac{7}{18}. Thus, D is the correct answer.

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Concepts: custom operation · mean · fraction

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.