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2012 AMC 10B Problem 10

Problem 10 of 25EasierNumber Theory

How many ordered pairs of positive integers (M,N)(M,N) satisfy the equation M6=6N\frac{M}{6}=\frac{6}{N}

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Solution

By cross multiplying, we can see that MN=36.MN = 36. Thus, we can make MM any factor of 3636 and then determine NN from it. Since 36=2232,36=2^2\cdot 3^2, we have (2+1)(2+1)=9(2+1)(2+1)=9 possible choices for M,M, each of which also determine a unique N.N. Thus, the correct answer is D .

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Concepts: factor counting · prime factorization

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.