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2007 AMC 12A Problem 23

Problem 23 of 25HarderAlgebraGeometry

Square ABCDABCD has area 36,36, and ABAB is parallel to the xx-axis. Vertices A,A, B,B, and CC are on the graphs of y=logax,y=\log_a x, y=2logax,y=2\log_a x, and y=3logax,y=3\log_a x, respectively. What is a?a?

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Solution

Let A=(p,logap)A=(p,\log_a p) and B=(q,2logaq).B=(q,2\log_a q). Since ABAB is horizontal, logap=2logaq=logaq2,\log_a p=2\log_a q=\log_a q^2, so p=q2.p=q^2. The side length is 6=pq=q2q,6=|p-q|=|q^2-q|, whose only positive solution is q=3.q=3. Since C=(q,3logaq),C=(q,3\log_a q), the vertical side gives BC=6=logaq=loga3.BC=6=\log_a q=\log_a 3. Thus a6=3,a^6=3, so a=36.a=\sqrt[6]{3}. Thus, the correct answer is A.

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Concepts: logarithm · coordinate geometry · square (geometry)

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.