Skip to main content

2003 AMC 10A Problem 5

Problem 5 of 25EasierAlgebra

Let dd and ee denote the solutions of 2x2+3x−5=0.2x^2 + 3x - 5 = 0. What is the value of (d−1)(e−1)?(d - 1)(e - 1)?

Answer choices

Show solution

Solution

Factoring gives 2x2+3x−5=(2x+5)(x−1),2x^2 + 3x - 5 = (2x + 5)(x - 1), so the roots are −52-\dfrac{5}{2} and 1.1. Since one root equals 1,1, one of the two factors d−1d-1 and e−1e-1 equals 0,0, making the product 0.0. Thus, the correct answer is B.
AoPS wiki

Tagged: quadratic · factoring

More practice