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2013 AMC 10A Problem 6

Problem 6 of 25Easier

Joey and his five brothers are ages 3,3, 5,5, 7,7, 9,9, 11,11, and 13.13. One afternoon two of his brothers whose ages sum to 1616 went to the movies, two brothers younger than 1010 went to play baseball, and Joey and the 55-year-old stayed home. How old is Joey?

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Solution

The age pairs that sum to 1616 are (3,13)(3,13), (5,11)(5,11), and (7,9)(7,9). The 55-year-old stayed home, so the movie pair cannot be (5,11)(5,11). If 77 and 99 went to the movies, then the only remaining brother younger than 1010 would be the 33-year-old, not enough for baseball. Thus the movie pair was (3,13)(3,13), the baseball pair was (7,9)(7,9), and Joey is the remaining brother, age 1111. Thus, D is the correct answer.

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Concepts: logical deduction · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.