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2016 AMC 10B Problem 1

Problem 1 of 25EasierAlgebra

What is the value of 2a1+a12a\dfrac{2a^{-1}+\frac{a^{-1}}{2}}{a} when a=12?a= \tfrac{1}{2}?

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Solution

The expression is equivalent to 2a2+a22=2.5(a1)2.2a^{-2}+\frac{a^{-2}}{2} = 2.5 (a^{-1})^2. Then a1a^{-1} is equal to 112=2,\dfrac{1}{\frac 12} = 2, so our expression is equal to 2.522=10.2.5\cdot 2^2 = 10. Thus, the correct answer is D .

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Concepts: exponent · substitution

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