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2017 AMC 10A Problem 15

Problem 15 of 25IntermediateCounting & Probability

Chloé chooses a real number uniformly at random from the interval [0,2017].[0, 2017]. Independently, Laurent chooses a real number uniformly at random from the interval [0,4034].[0, 4034]. What is the probability that Laurent’s number is greater than Chloé’s number?

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Solution

If Laurent chooses a number in the interval (2017,4034],(2017, 4034], then there is no way that Chloé can have the greater number. This means that Laurent has a 12\frac{1}{2} chance of automatically winning. Otherwise, Laurent chooses a number in the interval [0,2017].[0, 2017]. The probability that he gets a greater number than Chloé is the same as Chloé getting a greater number than Laurent. This means that Laurent has a 12\frac{1}{2} chance of getting a greater number (when working with real intervals, the probability of a tie is essentially 00 due to the infinite size of the intervals). Laurent’s total chance of getting a greater number is 121+1212=34. \dfrac{1}{2} \cdot 1 + \dfrac{1}{2} \cdot \dfrac{1}{2} = \dfrac{3}{4}. Thus, C is the correct answer.

More practice

Concepts: geometric probability · symmetry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.