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2024 AMC 10A Problem 4

Problem 4 of 25EasierAlgebra

The number 20242024 is written as the sum of not necessarily distinct two-digit numbers. What is the least number of two-digit numbers needed to write this sum?

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Solution

Each two-digit number is at most 99,99, so kk of them sum to at most 99k.99k. We need 99k2024,99k \ge 2024, which forces k20.4,k \ge 20.4, so k21.k \ge 21. And 2121 really works: twenty 9999s plus one 4444 give 1980+44=2024.1980 + 44 = 2024. Therefore, the answer is B.

More practice

Concepts: inequality · bounding to limit cases · optimization

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.