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2009 AMC 12B Problem 13

Problem 13 of 25IntermediateGeometryProblem-Solving Techniques

Triangle ABCABC has AB=13AB = 13 and AC=15,AC = 15, and the altitude to BCBC has length 12.12. What is the sum of the two possible values of BC?BC?

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Solution

Let DD be the foot of the altitude from A.A. Then BD=132−122=5BD = \sqrt{13^2 - 12^2} = 5 and DC=152−122=9.DC = \sqrt{15^2 - 12^2} = 9. If DD lies between BB and C,C, then BC=5+9=14BC = 5 + 9 = 14; if the triangle is obtuse, BC=9−5=4.BC = 9 - 5 = 4. The sum is 14+4=18.14 + 4 = 18. Thus, the correct answer is D.
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