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2009 AMC 12B Problem 3

Problem 3 of 25EasierAlgebra

Twenty percent less than 6060 is one-third more than what number?

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Solution

Twenty percent less than 6060 is 0.8⋅60=48.0.8 \cdot 60 = 48. One-third more than nn is 43n,\dfrac{4}{3}n, so 43n=48\dfrac{4}{3}n = 48 gives n=36.n = 36. Thus, the correct answer is D.

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Concepts: percentage · fraction · linear equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.