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2013 AMC 12A Problem 1

Problem 1 of 25EasierGeometry

Square ABCDABCD has side length 10.10. Point EE is on BC,\overline{BC}, and the area of ABE\triangle ABE is 40.40. What is BE?BE?

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Solution

The legs of right triangle ABEABE are AB=10AB = 10 and BE.BE. From 1210BE=40,\tfrac12\cdot 10\cdot BE = 40, we get BE=8.BE = 8. Thus, the correct answer is E.

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Concepts: triangle area · right triangle

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.