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2013 AMC 12B Problem 1

Problem 1 of 25EasierAlgebra

On a particular January day, the high temperature in Lincoln, Nebraska, was 1616 degrees higher than the low temperature, and the average of the high and low temperatures was 3∘.3^\circ. In degrees, what was the low temperature in Lincoln that day?

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Solution

The high exceeds the low by 16,16, so the low is 88 below the average. Since the average is 3∘,3^\circ, the low temperature is 3−8=−5∘.3 - 8 = -5^\circ. Thus, the correct answer is C.

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Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.