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2008/09 AHSMC Part 1 Problem 10

Problem 10 of 16

Linda is walking at constant speed halfway between two parallel train tracks. On each track is a train of the same length. They are approaching Linda from different directions, both at VV kilometres per hour. The one going the same way as Linda takes t1t_1 seconds to pass her, while the other takes t2t_2 seconds to pass her. In kilometres per hour, Linda's walking speed is

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Solution

Let Linda's walking speed be vv kilometres per hour. Then the length of the trains is given by t1(V−v)=t2(V+v)t_1(V - v) = t_2(V + v). It follows that v=t1−t2t1+t2Vv = \dfrac{t_1-t_2}{t_1+t_2}V. The answer is (A).