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2001 AMC 10 Problem 12

Problem 12 of 25IntermediateNumber Theory

Suppose that nn is the product of three consecutive integers and that nn is divisible by 7.7. Which of the following is not necessarily a divisor of n?n?

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Solution

Among three consecutive integers, at least one is even and one is a multiple of 3,3, so nn is divisible by 6.6. With the given factor of 7,7, it is divisible by 6,6, 14,14, 21,21, and 42.42. But 28=22728=2^2\cdot7 requires two factors of 2,2, which is not guaranteed: 567=2105\cdot6\cdot7=210 is divisible by 77 but not by 28.28. Thus, the correct answer is D.

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Concepts: divisibility · prime factorization · counterexample

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.