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2001 AMC 10 Problem 13

Problem 13 of 25IntermediateNumber Theory

A telephone number has the form ABCDEFGHIJ,ABC-DEF-GHIJ, where each letter represents a different digit. The digits in each part of the number are in decreasing order; that is, A>B>C,A\gt B\gt C, D>E>F,D\gt E\gt F, and G>H>I>J.G\gt H\gt I\gt J. Furthermore, D,D, E,E, and FF are consecutive even digits; G,G, H,H, I,I, and JJ are consecutive odd digits; and A+B+C=9.A+B+C=9. Find A.A.

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Solution

The consecutive odd digits GHIJGHIJ are 97539753 or 7531,7531, leaving one odd digit (11 or 99) for A,A, B,B, C.C. Since A+B+C=9,A+B+C=9, the odd digit there must be 1,1, so the two even digits in ABCABC sum to 8.8. The consecutive even digits DEFDEF are 864,864, 642,642, or 420,420, leaving even-digit pairs {2,0},\{2,0\}, {8,0},\{8,0\}, or {8,6}\{8,6\} for ABC.ABC. Only {8,0}\{8,0\} sums to 8,8, so ABC=810ABC=810 and A=8.A=8. Thus, the correct answer is E.

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Concepts: digits · logical deduction · casework

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