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2002 AMC 10B Problem 25

Problem 25 of 25HarderAlgebraProbability & Statistics

When 1515 is appended to a list of integers, the mean is increased by 2.2. When 11 is appended to the enlarged list, the mean of the enlarged list is decreased by 1.1. How many integers were in the original list?

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Solution

Let the original list have nn integers with mean m,m, so its sum is mn.mn. Appending 1515 gives (m+2)(n+1)=mn+15  ⟹  m+2n=13. \begin{aligned} &(m + 2)(n + 1) \\ &= mn + 15 \\ &\implies m + 2n = 13. \end{aligned} Appending 11 to that enlarged list gives (m+1)(n+2)=mn+16  ⟹  2m+n=14. \begin{aligned} &(m + 1)(n + 2) \\ &= mn + 16 \\ &\implies 2m + n = 14. \end{aligned} Solving m+2n=13m + 2n = 13 and 2m+n=142m + n = 14 yields m=5m = 5 and n=4.n = 4. Thus, the correct answer is A.
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