Skip to main content

2006 AMC 10A Problem 7

Problem 7 of 25EasierGeometry

The 8×188 \times 18 rectangle ABCDABCD is cut into two congruent hexagons, as shown, in such a way that the two hexagons can be repositioned without overlap to form a square. What is y?y?

Answer choices

Show solution

Solution

The rectangle’s area is 818=144,8 \cdot 18 = 144, so the square formed has side 144=12.\sqrt{144} = 12. Let EE and FF be the upper and lower endpoints of the stair-step cut. For the two congruent pieces to fit into a square, the three horizontal segments DE,DE, the middle segment of length y,y, and FBFB must be equal. Together they span the rectangle’s width, so DE+y+FB=18DE+y+FB=18 gives 3y=183y=18 and y=6.y=6. Indeed, the resulting square has side 2y=12,2y=12, agreeing with the area calculation. Thus, the correct answer is A.

More practice

Concepts: area · area decomposition

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.