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2008 AMC 10A Problem 15

Problem 15 of 25IntermediateAlgebra

Yesterday Han drove 11 hour longer than Ian at an average speed 55 miles per hour faster than Ian. Jan drove 22 hours longer than Ian at an average speed 1010 miles per hour faster than Ian. Han drove 7070 miles more than Ian. How many more miles did Jan drive than Ian?

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Solution

Let Ian drive tt hours at rate r,r, covering rtrt miles. Han drove (r+5)(t+1)rt(r + 5)(t + 1) - rt =5t+r+5=70,= 5t + r + 5 = 70, so 5t+r=65.5t + r = 65. Jan drove (r+10)(t+2)rt(r + 10)(t + 2) - rt =10t+2r+20= 10t + 2r + 20 =2(5t+r)+20= 2(5t + r) + 20 =265+20= 2 \cdot 65 + 20 =150= 150 miles more than Ian. Thus, the correct answer is D.

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Concepts: distance rate and time · system of equations · algebraic manipulation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.