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2008 AMC 10A Problem 4

Problem 4 of 25EasierAlgebra

Suppose that 23\dfrac{2}{3} of 1010 bananas are worth as much as 88 oranges. How many oranges are worth as much as 12\dfrac{1}{2} of 55 bananas?

Answer choices

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Solution

Since 23\dfrac{2}{3} of 1010 bananas is 203\dfrac{20}{3} bananas worth 88 oranges, one banana is worth 8÷203=658 \div \dfrac{20}{3} = \dfrac{6}{5} oranges. Now 12\dfrac{1}{2} of 55 bananas is 52\dfrac{5}{2} bananas, worth 5265=3\dfrac{5}{2} \cdot \dfrac{6}{5} = 3 oranges. Thus, the correct answer is C.

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Concepts: ratio and proportion · rate

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.