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2009 AMC 10A Problem 4

Problem 4 of 25EasierAlgebra

Eric plans to compete in a triathlon. He can average 22 miles per hour in the 14\tfrac14-mile swim and 66 miles per hour in the 33-mile run. His goal is to finish the triathlon in 22 hours. To accomplish his goal what must his average speed, in miles per hour, be for the 1515-mile bicycle ride?

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Solution

The swim takes 142=18\dfrac{\frac{1}{4}}{2} = \dfrac18 hour and the run takes 36=12\dfrac{3}{6} = \dfrac12 hour. This leaves 21812=1182 - \dfrac18 - \dfrac12 = \dfrac{11}{8} hours for the bicycle ride. His average speed must be 15118=12011\dfrac{15}{\frac{11}{8}} = \dfrac{120}{11} miles per hour. Thus, the correct answer is A.

More practice

Concepts: distance rate and time · fraction

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.