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2018 AMC 10B Problem 22

Problem 22 of 25HarderGeometryCounting & Probability

Real numbers xx and yy are chosen independently and uniformly at random from the interval [0,1].[0, 1]. Which of the following numbers is closest to the probability that x,x, y,y, and 11 are the side lengths of an obtuse triangle?

Answer choices

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Solution

The three lengths x,y,1x, y, 1 make a triangle iff x+y>1.x + y > 1. Since 11 is the longest side, that triangle is obtuse iff x2+y2<1.x^2 + y^2 < 1. So in the unit square we want the region inside the quarter circle x2+y2=1x^2 + y^2 = 1 but above the line x+y=1.x + y = 1. That’s the quarter disk with the right triangle under the chord removed: π4120.285.\tfrac{\pi}{4} - \tfrac12 \approx 0.285. The closest choice is 0.29.0.29. Therefore, the answer is C.

More practice

Concepts: geometric probability · law of cosines

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.