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2018 AMC 10B Problem 8

Problem 8 of 25EasierAlgebra

Sara makes a staircase out of toothpicks as shown: This is a 33-step staircase and uses 1818 toothpicks. How many steps would be in a staircase that used 180180 toothpicks?

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Solution

In an nn-step staircase the vertical toothpicks number (1+2++n)+n(1 + 2 + \cdots + n) + n =n(n+1)2+n,= \tfrac{n(n+1)}{2} + n, and there are just as many horizontal ones. That’s a total of n(n+1)+2n=n(n+3).n(n+1) + 2n = n(n+3). Check: n=3n = 3 gives 18,18, as it should. Now solve n(n+3)=180.n(n+3) = 180. This factors as (n12)(n+15)=0,(n-12)(n+15) = 0, so n=12.n = 12. Therefore, the answer is C.

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Concepts: quadratic · summation · pattern recognition

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.