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2018 AMC 10B Problem 3

Problem 3 of 25EasierCounting & Probability

In the expression (x×x)+(x×x)(\underline{\phantom{x}} \times \underline{\phantom{x}}) + (\underline{\phantom{x}} \times \underline{\phantom{x}}) each blank is to be filled in with one of the digits 1,1, 2,2, 3,3, or 4,4, with each digit being used once. How many different values can be obtained?

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Solution

Order inside a product doesn’t matter, and neither does the order we add the two products. So all that matters is how the four digits split into two pairs. There are three splits: 12+34=14,1\cdot2 + 3\cdot4 = 14, 13+24=11,1\cdot3 + 2\cdot4 = 11, and 14+23=10.1\cdot4 + 2\cdot3 = 10. That’s 33 different values. Thus, B is the correct answer.

More practice

Concepts: basic counting · systematic listing

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.