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2020 AMC 10B Problem 10

Problem 10 of 25EasierGeometry

A three-quarter sector of a circle of radius 44 inches together with its interior can be rolled up to form the lateral surface of a right circular cone by taping together along the two radii shown. What is the volume of the cone in cubic inches?

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Solution

The sector’s arc becomes the base circumference, so if the base radius is r,r, then 2πr=34(2π4)=6π,2\pi r=\frac34(2\pi\cdot4)=6\pi, giving r=3.r=3. The sector radius becomes the cone’s slant height, so the cone’s height is h=4232=7.h=\sqrt{4^2-3^2}=\sqrt7. Hence the volume is 13πr2h=13π(3)27=3π7.\frac13\pi r^2h=\frac13\pi(3)^2\sqrt7=3\pi\sqrt7. Thus, C is the correct answer.

More practice

Concepts: cone · net (3D geometry) · Pythagorean Theorem

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.