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2024 AMC 10B Problem 21

Problem 21 of 25HarderGeometry

Two straight pipes (circular cylinders), with radii 11 and 14,\tfrac14, lie parallel and in contact on a flat floor. The figure below shows a head-on view. What is the sum of the possible radii of a third parallel pipe lying on the same floor and in contact with both?

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Solution

Two circles of radii RR and rr resting on the floor and touching each other have contact points a horizontal distance 2Rr2\sqrt{Rr} apart. So the radius-11 and radius-14\tfrac14 pipes touch the floor 2114=12\sqrt{1 \cdot \tfrac14} = 1 apart. A third pipe of radius rr sits 2r2\sqrt{r} from the big pipe’s contact point and 214r=r2\sqrt{\tfrac14 r} = \sqrt{r} from the small pipe’s. Nestled between them, 2r+r=1,2\sqrt r + \sqrt r = 1, so r=13\sqrt r = \tfrac13 and r=19.r = \tfrac19. Sitting past the small pipe, 2rr=1,2\sqrt r - \sqrt r = 1, so r=1.r = 1. (Past the big pipe can’t happen.) The sum is 19+1=109.\tfrac19 + 1 = \tfrac{10}{9}. Thus, C is the correct answer.

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Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.