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2002 AMC 12B Problem 17

Problem 17 of 25IntermediateArithmetic

Andy’s lawn has twice as much area as Beth’s lawn and three times as much area as Carlos’ lawn. Carlos’ lawn mower cuts half as fast as Beth’s mower and one third as fast as Andy’s mower. If they all start to mow their lawns at the same time, who will finish first?

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Solution

Let Andy’s lawn have area A;A; then Beth’s is A2\dfrac A2 and Carlos’ is A3.\dfrac A3. With Carlos’ rate R,R, Beth mows at 2R2R and Andy at 3R.3R. Their times are A3R,\dfrac{A}{3R}, A22R=A4R,\dfrac{\frac{A}{2}}{2R}=\dfrac{A}{4R}, and A3R=A3R\dfrac{\frac{A}{3}}{R}=\dfrac{A}{3R} respectively. Beth’s time A4R\dfrac{A}{4R} is the smallest, so Beth finishes first. Thus, the correct answer is B.
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