Skip to main content

2005 AMC 12A Problem 16

Problem 16 of 25IntermediateGeometry

Three circles of radius ss are drawn in the first quadrant of the xyxy-plane. The first circle is tangent to both axes, the second is tangent to the first circle and the xx-axis, and the third is tangent to the first circle and the yy-axis. A circle of radius r>sr \gt s is tangent to both axes and to the second and third circles. What is rs?\frac{r}{s}?

Answer choices

Show solution

Solution

Put the big circle’s center at (r,r)(r, r) and the second small circle’s center at (3s,s).(3s, s). They are externally tangent, so the distance between centers is r+s.r + s. The horizontal and vertical gaps are r3sr - 3s and rs,r - s, so (r+s)2=(r3s)2+(rs)2. (r + s)^2 = (r - 3s)^2 + (r - s)^2. Expanding gives 0=r210rs+9s20 = r^2 - 10rs + 9s^2 =(r9s)(rs).= (r - 9s)(r - s). Since rs,r \ne s, we get r=9s,r = 9s, so rs=9.\frac{r}{s} = 9. Thus, the correct answer is D.

More practice

Concepts: tangent circles · coordinate geometry · Pythagorean Theorem

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.