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2012 AMC 12A Problem 23

Problem 23 of 25HarderGeometryCounting & Probability

Let SS be the square one of whose diagonals has endpoints (0.1,0.7)(0.1, 0.7) and (0.1,0.7).(-0.1, -0.7). A point v=(x,y)v = (x, y) is chosen uniformly at random over all pairs of real numbers xx and yy such that 0x20120 \le x \le 2012 and 0y2012.0 \le y \le 2012. Let T(v)T(v) be a translated copy of SS centered at v.v. What is the probability that the square region determined by T(v)T(v) contains exactly two points with integer coordinates in its interior?

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Solution

The diagonal from (0.1,0.7)(0.1, 0.7) to (0.1,0.7)(-0.1, -0.7) has length 0.22+1.42=2,\sqrt{0.2^2 + 1.4^2} = \sqrt2, so SS is a square of area 1.1. The translate T(v)T(v) contains a lattice point exactly when vv lies inside the copy of SS centered at that point. Containing exactly two interior lattice points requires vv to lie in the overlap of two copies centered at adjacent lattice points. By periodicity the answer is the total such overlap area within one unit cell. Consider copies centered at (0,0)(0,0) and (1,0).(1,0). Their overlap is a rectangle. A quarter-turn of the listed half-diagonal gives the relevant vertices (0.7,0.1)(0.7,-0.1) and (0.3,0.1).(0.3,0.1). Following the two pairs of parallel sides through their intersections gives side lengths 0.40.4 and 0.2,0.2, so the overlap area is 0.08.0.08. Diagonally centered copies do not overlap, and horizontal and vertical adjacencies contribute equally. Accounting for the cell boundaries gives probability 20.08=0.16.2\cdot0.08=0.16. Thus, the correct answer is C.

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Concepts: geometric probability · lattice point · area

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.