2012 AMC 12A Problem 7

Let $a$ be the smallest angle and $d \ge 0$ the common difference. The sum of the angles is $12a + 66d = 360,$ so $2a + 11d = 60.$ To make $a$ small, take $d$ large. Since $11d$ must be even, $d$ is even, and $d = 4$ gives $2a = 60 - 44 = 16,$ so $a = 8.$ A larger even $d$ makes $a$ non-positive. Thus, the correct answer is C.