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2015 AMC 12B Problem 11

Problem 11 of 25IntermediateGeometry

The line 12x+5y=6012x + 5y = 60 forms a triangle with the coordinate axes. What is the sum of the lengths of the altitudes of this triangle?

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Solution

The line meets the axes at (5,0)(5, 0) and (0,12),(0, 12), so the triangle is right with legs 55 and 1212 and hypotenuse 13.13. Its area is 30.30. Two altitudes are the legs 55 and 12;12; the altitude to the hypotenuse is 23013=6013.\dfrac{2 \cdot 30}{13} = \dfrac{60}{13}. The sum is 17+6013=28113.17 + \dfrac{60}{13} = \dfrac{281}{13}. Thus, the correct answer is E.

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Concepts: coordinate geometry · right triangle · altitude

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.