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2015 AMC 12B Problem 5

Problem 5 of 25EasierAlgebra

The Tigers beat the Sharks 22 out of the first 33 times they played. They then played NN more times, and the Sharks ended up winning at least 95%95\% of all the games played. What is the minimum possible value for N?N?

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Solution

The Sharks won 11 of the first 33 games. To reach 95%95\% with the fewest extra games, they should win all NN additional games, giving a win fraction 1+N3+N.\dfrac{1 + N}{3 + N}. Requiring 1+N3+N1920\dfrac{1 + N}{3 + N} \ge \dfrac{19}{20} gives 20+20N57+19N,20 + 20N \ge 57 + 19N, so N37.N \ge 37. Thus, the correct answer is B.

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Concepts: percentage · inequality · extremal argument

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.