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2017 AMC 12B Problem 4

Problem 4 of 25EasierAlgebra

Samia set off on her bicycle to visit her friend, traveling at an average speed of 1717 kilometers per hour. When she had gone half the distance to her friend’s house, a tire went flat, and she walked the rest of the way at 55 kilometers per hour. In all it took her 4444 minutes to reach her friend’s house. In kilometers rounded to the nearest tenth, how far did Samia walk?

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Solution

Let 2d2d be the total distance, so she biked dd at 1717 km/h and walked dd at 55 km/h. The total time in hours is d17+d5=4460.\frac{d}{17} + \frac{d}{5} = \frac{44}{60}. Combining the left side gives 22d85=1115,\dfrac{22d}{85} = \dfrac{11}{15}, so d=11158522=176=2.833d = \dfrac{11}{15} \cdot \dfrac{85}{22} = \dfrac{17}{6} = 2.833\ldots She walked about 2.82.8 kilometers. Thus, the correct answer is C.

More practice

Concepts: distance rate and time · linear equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.