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2021 AMC 12B Problem 10

Problem 10 of 25EasierAlgebra

Two distinct numbers are selected from the set {1,2,3,4,,36,37}\{1,2,3,4,\ldots,36,37\} so that the sum of the remaining 3535 numbers is the product of these two numbers. What is the difference of these two numbers?

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Solution

The sum 1+2++37=703.1+2+\cdots+37=703. If the chosen numbers are aa and b,b, then 703ab=ab.703-a-b=ab. So ab+a+b=703,ab+a+b=703, and adding 11 gives (a+1)(b+1)=704=2611.(a+1)(b+1)=704=2^6\cdot 11. We need factors a+1,b+1a+1,b+1 between 22 and 38.38. The pair 2232=70422\cdot 32=704 works, giving a=21,a=21, b=31.b=31. Their difference is 3121=10.31-21=10. Thus, the correct answer is E.

More practice

Concepts: Simon’s Favorite Factoring Trick · arithmetic sequence

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.