2024 AMC 12B Problem 2Problem 2 of 25·Easier·ArithmeticWhat is 10!−7!⋅6!?10! - 7! \cdot 6!?10!−7!⋅6!?Answer choicesA−120-120−1201B0002C1201201203D6006006004E7207207205Submit answerStuck? Show hintsShow solutionSolutionNote that 6!=720=8⋅9⋅10.6! = 720 = 8 \cdot 9 \cdot 10.6!=720=8⋅9⋅10. Therefore 7!⋅6!=7!⋅(8⋅9⋅10)=10!.7! \cdot 6! = 7! \cdot (8 \cdot 9 \cdot 10) = 10!.7!⋅6!=7!⋅(8⋅9⋅10)=10!. So 10!−7!⋅6!=10!−10!=0.10! - 7! \cdot 6! = 10! - 10! = 0.10!−7!⋅6!=10!−10!=0. Thus, the correct answer is B.AoPS wikiCopy problemTagged: factorial