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2024 AMC 12B Problem 5

Problem 5 of 25EasierAlgebra

In the following expression, Melanie changed some of the plus signs to minus signs: 1+3+5+7++97+991 + 3 + 5 + 7 + \cdots + 97 + 99 When the new expression was evaluated, it was negative. What is the least number of plus signs that Melanie could have changed to minus signs?

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Solution

The original expression sums the first 5050 odd numbers, giving 502=2500.50^2 = 2500. Changing a term of value vv from ++ to - decreases the total by 2v,2v, so to make the result negative the flipped terms must total more than 25002=1250.\dfrac{2500}{2} = 1250. To use as few terms as possible, flip the largest odd numbers 99,97,95,99, 97, 95, \ldots The largest kk of them sum to k(100k).k(100 - k). With k=14k = 14 this is 1486=12041250,14 \cdot 86 = 1204 \le 1250, but with k=15k = 15 it is 1585=1275>1250.15 \cdot 85 = 1275 \gt 1250. So 1515 sign changes suffice and 1414 do not. Thus, the correct answer is B.

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Concepts: arithmetic sequence · optimization

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.