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2003 AMC 10B Problem 24

Problem 24 of 25HarderAlgebra

The first four terms in an arithmetic sequence are x+y,x+y, x−y,x-y, xy,xy, and xy,\frac{x}{y}, in that order. What is the fifth term?

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Solution

The common difference is −2y,-2y, so the third and fourth terms must be x−3yx-3y and x−5y.x-5y. Thus xy=x−3yxy=x-3y and xy=x−5y.\dfrac{x}{y}=x-5y. From xy=x−5y\dfrac{x}{y}=x-5y we get x=xy−5y2,x=xy-5y^2, and substituting xy=x−3yxy=x-3y gives −3y−5y2=0.-3y-5y^2=0. Since y≠0,y\ne 0, y=−35y=-\dfrac35 and then x=−98.x=-\dfrac98. The fifth term is x−7y=−98+215=12340.x-7y=-\dfrac98 + \dfrac{21}{5}=\dfrac{123}{40}. Thus, the correct answer is E.
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