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2005 AMC 10B Problem 4

Problem 4 of 25EasierAlgebra

For real numbers aa and b,b, define a⋄b=a2+b2.a \diamond b = \sqrt{a^2 + b^2}. What is the value of (5⋄12)⋄((−12)⋄(−5))?(5 \diamond 12) \diamond ((-12) \diamond (-5))?

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Solution

Each inner expression evaluates to 5⋄12=52+122=13 5 \diamond 12 = \sqrt{5^2 + 12^2} = 13 and similarly (−12)⋄(−5)(-12) \diamond (-5) =144+25=13.= \sqrt{144 + 25} = 13. Then 13⋄13=132+132=132. 13 \diamond 13 = \sqrt{13^2 + 13^2} = 13\sqrt{2}. Thus, D is the correct answer.
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