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2005 AMC 10B Problem 9

Problem 9 of 25EasierNumber TheoryCounting & Probability

One fair die has faces 1,1, 1,1, 2,2, 2,2, 3,3, 33 and another has faces 4,4, 4,4, 5,5, 5,5, 6,6, 6.6. The dice are rolled and the numbers on the top faces are added. What is the probability that the sum will be odd?

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Solution

The first die is odd (a 11 or 33) with probability 23\dfrac23 and even with probability 13.\dfrac13. The second die is odd (a 55) with probability 13\dfrac13 and even with probability 23.\dfrac23. The sum is odd when the two parities differ: 1313+2323=19+49=59. \dfrac13 \cdot \dfrac13 + \dfrac23 \cdot \dfrac23 = \dfrac19 + \dfrac49 = \dfrac59. Thus, D is the correct answer.

More practice

Concepts: dice (probability) · parity · independent events

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.