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2014 AMC 10B Problem 12

Problem 12 of 25IntermediateNumber Theory

The largest divisor of 2,014,000,0002{,}014{,}000{,}000 is itself. What is its fifth-largest divisor?

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Solution

The fifth-largest divisor is 2,014,000,0002,014,000,000 divided by the fifth smallest divisor. The prime factorization of 2,014,000,0002,014,000,000 is: 27561953.2^7\cdot 5^6 \cdot 19\cdot 53. This makes the first 55 smallest divisors 1,2,4,5,8.1,2,4,5,8. Therefore, the fifth smallest divisor is 8,8, and the fifth largest divisor must be: 20140000008=251750000.\dfrac{2014000000}8 =251750000. Thus, the correct answer is C .

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Concepts: factor · prime factorization

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.