2014 AMC 10B Problem 12
Problem 12 of 25IntermediateNumber Theory
The largest divisor of is itself. What is its fifth-largest divisor?
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Solution
The fifth-largest divisor is divided by the fifth smallest divisor.
The prime factorization of is: This makes the first smallest divisors Therefore, the fifth smallest divisor is and the fifth largest divisor must be:
Thus, the correct answer is C .