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2014 AMC 10B Problem 7

Problem 7 of 25EasierAlgebra

Suppose A>B>0A > B > 0 and AA is x%x\% greater than B.B. What is x?x?

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Solution

By definition, we know A=x+100100BA = \dfrac {x+ 100}{100}B =B+x100B.= B + \dfrac x{100}B. This implies, (AB)=x100B100(ABB)=x.\begin{aligned} (A-B) &= \dfrac x{100}B\\ 100\left(\dfrac{A-B} B\right) &=x.\end{aligned} Thus, the correct answer is A .

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Concepts: percentage · algebraic manipulation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.