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2014 AMC 10B Problem 9

Problem 9 of 25EasierAlgebraArithmetic

For real numbers w w and z, z , 1w+1z1w−1z=2014. \cfrac{\frac{1}{w} + \frac{1}{z}}{\frac{1}{w} - \frac{1}{z}} = 2014. What is w+zw−z? \frac{w+z}{w-z} ?

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Solution

Observe that: wzwz⋅1w+1z1w−1z=2014w+zz−w=2014w+zw−z=−1⋅2014w+zw−z=−2014.\begin{aligned} \dfrac{wz}{wz}\cdot \dfrac{\frac{1}{w} + \frac{1}{z}}{\frac{1}{w} - \frac{1}{z}} &= 2014\\ \dfrac{w+z}{z-w} &= 2014\\ \dfrac{w+z}{w-z} &= -1\cdot 2014\\ \dfrac{w+z}{w-z}&=-2014.\end{aligned} Thus, the correct answer is A .
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