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2015 AMC 10A Problem 1

Problem 1 of 25EasierAlgebra

What is the value of the following expression? (20−1+52+0)−1×5(2^0-1+5^2+0)^{-1} \times 5

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Solution

We can evaluate it as follows. (20−1+52+0)−1×5=11−1+25×5=525=15\begin{aligned} &(2^0-1+5^2+0)^{-1} \times 5 \\&=\dfrac{1}{1 - 1 + 25} \times 5 \\ &= \dfrac{5}{25}\\ &= \dfrac{1}{5} \end{aligned} Thus, C is the correct answer.

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Concepts: order of operations · exponent

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