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2025 AMC 10A Problem 13

Problem 13 of 25IntermediateAlgebraGeometry

In the figure below, the outside square contains infinitely many squares, each of them with the same center and sides parallel to the outside square. The ratio of the side length of a square to the side length of the next inner square is k,k, where 0<k<1.0 \lt k \lt 1. The spaces between squares are alternately shaded, as shown in the figure (which is not necessarily drawn to scale). The area of the shaded portion of the figure is 64%64\% of the area of the original square. What is k?k?

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Solution

Let the outer side be 1.1. The squares have sides 1,k,k2,,1, k, k^2, \ldots, and the shaded rings alternate, so the shaded area is 1k2+k4k6+=11+k2.1 - k^2 + k^4 - k^6 + \cdots = \frac{1}{1 + k^2}. We’re told this equals 64%=1625,64\% = \frac{16}{25}, so 1+k2=2516.1 + k^2 = \frac{25}{16}. Then k2=916,k^2 = \frac{9}{16}, giving k=34.k = \frac{3}{4}. Thus, D is the correct answer.

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Concepts: geometric sequence · area ratio

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.