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2002 AMC 12A Problem 15

Problem 15 of 25IntermediateAlgebra

The mean, median, unique mode, and range of a collection of eight integers are all equal to 8.8. The largest integer that can be an element of this collection is

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Solution

The collection 6,6,6,8,8,8,8,146, 6, 6, 8, 8, 8, 8, 14 has mean, median, unique mode, and range all equal to 8,8, so 1414 is attainable. Suppose the largest were 15.15. The range 88 forces the smallest to be 7.7. Because 88 is the mode, it occurs in the sorted list; together with median 8,8, this forces the two middle values to be 8,8.8, 8. Then 7+8+8+15=38,7 + 8 + 8 + 15 = 38, so the remaining four values sum to 6438=26,64 - 38 = 26, averaging 6.5.6.5. At least one would be below 7,7, contradicting the minimum. So 1515 is impossible. Thus, the correct answer is D.

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Concepts: mean · range · extremal argument

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.