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2002 AMC 12A Problem 7

Problem 7 of 25EasierAlgebraGeometry

If an arc of 4545^\circ on circle AA has the same length as an arc of 3030^\circ on circle B,B, then the ratio of the area of circle AA to the area of circle BB is

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Solution

Equal arc lengths give 453602πRA=303602πRB,\dfrac{45}{360}\cdot 2\pi R_A = \dfrac{30}{360}\cdot 2\pi R_B, so RARB=3045=23.\dfrac{R_A}{R_B} = \dfrac{30}{45} = \dfrac{2}{3}. The ratio of areas is (RARB)2=49.\left(\dfrac{R_A}{R_B}\right)^2 = \dfrac{4}{9}. Thus, the correct answer is A.

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Concepts: arc · circle area · ratio and proportion

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.