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2006 AMC 12B Problem 8

Problem 8 of 25EasierAlgebra

The lines x=14y+a,y=14x+bx = \tfrac14 y + a, \qquad y = \tfrac14 x + b intersect at the point (1,2).(1, 2). What is a+b?a + b?

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Solution

Substituting (1,2)(1, 2) gives 1=24+a⇒a=12,1 = \frac{2}{4} + a \quad\Rightarrow\quad a = \frac{1}{2}, and 2=14+b⇒b=74.2 = \frac{1}{4} + b \quad\Rightarrow\quad b = \frac{7}{4}. Therefore a+b=12+74=94.a + b = \frac{1}{2} + \frac{7}{4} = \frac{9}{4}. Thus, the correct answer is E.
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