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2008 AMC 12A Problem 12

Problem 12 of 25IntermediateAlgebra

A function ff has domain [0,2][0, 2] and range [0,1].[0, 1]. (The notation [a,b][a, b] denotes {x:axb}.\{x : a \le x \le b\}.) What are the domain and range, respectively, of the function gg defined by g(x)=1f(x+1)?g(x) = 1 - f(x + 1)?

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Solution

The value f(x+1)f(x + 1) is defined when 0x+12,0 \le x + 1 \le 2, that is, 1x1,-1 \le x \le 1, so the domain of gg is [1,1].[-1, 1]. As f(x+1)f(x + 1) ranges over [0,1],[0, 1], the value 1f(x+1)1 - f(x + 1) ranges over [0,1][0, 1] as well, so the range of gg is [0,1].[0, 1]. Thus, B is the correct answer.

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Concepts: function

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.