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2008 AMC 12A Problem 12

Problem 12 of 25IntermediateAlgebra

A function ff has domain [0,2][0, 2] and range [0,1].[0, 1]. (The notation [a,b][a, b] denotes {x:a≤x≤b}.\{x : a \le x \le b\}.) What are the domain and range, respectively, of the function gg defined by g(x)=1−f(x+1)?g(x) = 1 - f(x + 1)?

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Solution

The value f(x+1)f(x + 1) is defined when 0≤x+1≤2,0 \le x + 1 \le 2, that is, −1≤x≤1,-1 \le x \le 1, so the domain of gg is [−1,1].[-1, 1]. As f(x+1)f(x + 1) ranges over [0,1],[0, 1], the value 1−f(x+1)1 - f(x + 1) ranges over [0,1][0, 1] as well, so the range of gg is [0,1].[0, 1]. Thus, B is the correct answer.
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