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2008 AMC 12A Problem 9

Problem 9 of 25EasierAlgebraGeometry

Older television screens have an aspect ratio of 4:3.4:3. That is, the ratio of the width to the height is 4:3.4:3. The aspect ratio of many movies is not 4:3,4:3, so they are sometimes shown on a television screen by “letterboxing” — darkening strips of equal height at the top and bottom of the screen, as shown. Suppose a movie has an aspect ratio of 2:12:1 and is shown on an older television screen with a 2727-inch diagonal. What is the height, in inches, of each darkened strip?

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Solution

Since the sides and diagonal are in ratio 3:4:5,3:4:5, the height is 3527=16.2\tfrac{3}{5} \cdot 27 = 16.2 inches and the width is 4527=21.6\tfrac{4}{5} \cdot 27 = 21.6 inches. The movie has aspect ratio 2:1,2:1, so its height is 21.62=10.8\tfrac{21.6}{2} = 10.8 inches. Each darkened strip therefore has height 16.210.82=2.7 \dfrac{16.2 - 10.8}{2} = 2.7 inches. Thus, D is the correct answer.

More practice

Concepts: Pythagorean Triple · ratio and proportion

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.